Question

A certain amount of ice is supplied heat at a constant rate for 7 minutes. For the first one minute, the temperature rises uniformly with time. Then it remains constant for the next 4 minutes and again the temperature rises at a uniform rate for the last two minutes. Calculate the final temperature at the end of seven minutes in celsius (Given L of ice = $336\times {10}^3$ J/kg and specific heat of water = 4200 J/kg - K)

Answer 1

Heat flow rate will be

$q^{\prime }=\frac{m\left(336X{10}^3\right)}{4}=m\left(84X{10}^3\right)$

Also, for last part $q^{\prime }=\frac{m\left(4200\right)(T-0)}{2}=2100mT$

Hence,

$2100T=84000$

$T={40}^{0}C$

Answer is ${40}^{0}C$