A certain amount of water is dissociated to produce oxygen which was just sufficient to burn magnesium to form 400 g of magnesium oxide. Calculate the amount of water dissociated.

90 g

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45 g

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180 g

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360 g

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Solution

The correct option is D 180 g
Mass of magnesium oxide = 400g
reaction equation is :
2mg + $O_{2} \to 2 M g O$
moles of mgo = $\frac{400 (g)}{40 (g / m o l)}$ = 10
a moles of mgo require 1 mol of o2 , 10 moles of mgo require 10 mole of o2
hense 10 moles of water used for produce oxygen , mass of water is

$10 m o l \times 18 g / m o l$ = 180g
answer is C

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Q. 4.8 g of magnesium on burning with same amount of oxygen gives magnesium oxide. Calculate the amount of product formed.

Q. When water is added to magnesium oxide ,magnesium hydroxide is produced which is also present in lime water .So, is it correct that the magnesium hydroxide present in lime water and the magnesium hydroxide formed from magnesium oxide and water are one and the same?

Hydrogen is generated by the action of steam with heated magnesium. Calculate the mass of magnesium which will produce just sufficient hydrogen to combine with all the oxygen that can be obtained by the complete decomposition of 24.5 g of $K C l O_{3}$ .

Which of the following statements indicates that law of multiple proportion is being followed ?

(a) Sample of carbon dioxide taken from any source will always have carbon and oxygen in the ratio 1 : 2

(b) Carbon forms two oxides namely $C O_{2}$ and CO, where masses of oxygen which combine with fixed mass of carbon are in the simple ratio 2 : 1

(c) When magnesium burns in oxygen, the amount of magnesium taken for the reactoin is equal to the amount of magnesium in magnesium oxide formed

(d) At constant temperature and pressure 200 mL of hydrogen will combine with 100 mL oxygen to produce 200 mL of water vapour

combustion reaction produce carbon dioxide and water so

Is magnesium + oxygen -------> magnesium oxide

a combustion reaction if yes then why heat , water and co2 didn't produce

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