1
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Question

# A certain block weighs 22 N in air. It weighs 17 N when immersed in water. When immersed in another liquid it weighs 18 N. Calculate the relative density of the other liquid.

A
0.8
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B
0.67
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C
0.2
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D
1
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Solution

## The correct option is A 0.8Let the relative density of the block be rb and that of the liquid be rlDensity of water be ρ⇒ Density of metal is rbρ and density of liquid is rlρLet the volume of the block be VWeight of the block in air is W1=rbρVg=22NWeight of the block in water is W2=(rb−1)ρVg=17NWeight of the block in the liquid is W3=(rb−rl)ρVg=18NThus, dividing W2 by W1, we getW2W1=rb−1rb=1722⇒rb=225=4.4Dividing W3 by W1, we getW3W1=rb−rlrb=1822⇒4.4−rl4.4=911⇒rl=0.8

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