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Question

A certain buffer solution contains equal concentration of X and HX. The Ka for HX is 108. The pH of the buffer is:

A
3
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B
8
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C
11
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D
14
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Solution

The correct option is A 8
As the value of Ka is given to us, it is an indication that the given buffer is an example of an acidic buffer.
Hence, we use the following formula for calculating its pH.

pH=logKw+log[Conjugatebase][Acid]

pH=pKa + log10[X][HX]=log10108 + log101=8
(As the concentrations of X and HX are equal)

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