A certain car uses 12 litres of petrol in traveling 240 kms. In order for the car to travel the same distance using 10 litres of petrol, by how what percentage must the car’s mileage in kms per litre be increased?

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Solution

The correct option is A 20
Initial mileage = 20 $\frac{k m s}{l t r}$
To travel 240 kms with 10 ltrs, mileage should be = $\frac{240}{10}$ = 24 $\frac{k m s}{l t r}$ ;
$%$ increase = $\frac{(24 - 20)}{20} \times 100 = 20 %$

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Q. Car travels

x k m

for every litre of petrol, while car

B

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(x + 1) k m

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B

for the journey.

Question 78

A car can travel 240km in 15 litres of petrol. How much distance will it travel in 25 litres of petrol?

Car A travels km for every litre of petrol, while car B travels ( + 5) km for every litre.

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A certain car uses 12 litres of petrol in traveling 240 kms. In order for the car to travel the same distance using 10 litres of petrol, by how what percentage must the car’s mileage in kms per litre be increased?

The correct option is A 20Initial mileage = 20 kmsltr To travel 240 kms with 10 ltrs, mileage should be = 24010 = 24 kmsltr ; % increase = (24−20)20×100=20%

The correct option is A 20
Initial mileage = 20 $\frac{k m s}{l t r}$
To travel 240 kms with 10 ltrs, mileage should be = $\frac{240}{10}$ = 24 $\frac{k m s}{l t r}$ ;
$%$ increase = $\frac{(24 - 20)}{20} \times 100 = 20 %$