A certain current liberated $0.504$ g of hydrogen in $2$ hrs. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution?

12.7

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16.5

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31.8

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63.5

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Solution

The correct option is B $16.5$ g
The equivalent weight of copper $= 32.7 g / e q$

The equivalent weight of hydrogen $= 1 g / e q$

Mass of hydrogen liberated = $0.504 g$

Substitute values in the equation $\frac{M a s s o f C u d e p o s i t e d}{M a s s o f h y d r o g e n l i b e r a t e d} = \frac{E q . W t o f C u}{E q . W t . o f H_{2}}$

$\frac{M a s s o f C u d e p o s i t e d}{0.504} = \frac{32.7}{1}$

$M a s s o f C u d e p o s i t e d = 0.504 \times 32.7 = 16.5 g$

Hence, option $B$ is correct.

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