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Question

A certain current on passing through a galvanometer produces a deflection of 100 divisions. When a shunt of one ohm is connected, the deflection reduces to 1 division. The galvanometer resistance is

A
100Ω
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B
99Ω
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C
10Ω
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D
9.9Ω
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Solution

The correct option is C 99Ω
Ig=kθ where k = galvanometer constant and θ is angular displacement (number of divisions)
GIven S=1Ω, I=100k and Ig=1k
Substituting above values in give concept attached we get G=99Ω

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