Question

A certain current on passing through a galvanometer produces a deflection of $100$ divisions. When a shunt of one ohm is connected, the deflection reduces to $1$ division. The galvanometer resistance is

• A. $100\Omega$
• B. $99\Omega$
• C. $10\Omega$
• D. $9.9\Omega$

Answer 1

Answer: (B)

$99\Omega$

$I_g=k\theta$ where k = galvanometer constant and $\theta$ is angular displacement (number of divisions)

GIven $S=1\Omega$, $I=100k$ and $I_g=1k$

Substituting above values in give concept attached we get $G=99\Omega$