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Question

A certain diatomic molecule, AB has dipole moment 1.6 D and the internuclear distance is 100 pm. The percentage of electronic charge existing on more electronegative atom is

A
33 %
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B
25 %
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C
50 %
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D
10 %
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Solution

The correct option is A 33 %
% ionic character = μobservedμionic * 100μobserved

=1.6D=1.6×1030cm(since 1 D = 10−30 cm)

μionic =q×dq=4.8×1010

esu =4.8×108

D =4.8×108×1030cm

d =100pm=100×1010cm%

ionic character = μobservedμionic * 100

=1.6×10304.8×108×1030×100×1010×100

=33.33%

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