Question

A certain diatomic molecule, $AB$ has dipole moment $1.6D$ and the inter-nuclear distance is $100pm$. The percentage of electronic charge existing on more electronegative atom is:

• A. $33$%
• B. $25$%
• C. $50$%
• D. $10$%

Answer 1

Answer: (A)

$33$%

% of ionic character= observed ionic × 100observed = $1.6D$ =$1.6\times 10-30cm(since1D=10-30cm)$

$ionic=q\times dq=4.8\times 10-10$

$esu=4.8\times 108D=4.8\times 108\times 10-30cm(since1D=10-18esu)$

$d=100pm=100\times 10-10cm$

$4.8\times 108\times 10-30\times 100\times 10-10\times 100=33.33$

Therefore, $33.33$ is the answer.