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Question

A certain engine which operates in a Carnot cycle absorbs 3.347 kJ at 400C, how much work is done by the engine per cycle? The temperature of sink is 100C.
  1. 1.49 kJ
  2. 2.98 kJ
  3. 1.85 kJ
  4. 2.51 kJ


Solution

The correct option is A 1.49 kJ
η=T2T1T2=1T1T2=1373673=0.446η=wq1 or W=η×q1=0.446×3.347=1.49kJ

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