Question

A certain engine which operates in a Carnot cycle absorbs 3.347 kJ at ${400}^{\circ }C,$ how much work is done by the engine per cycle? The temperature of sink is ${100}^{\circ }C.$

• A. 1.49 kJ
• B. 2.51 kJ
• C. 1.85 kJ
• D. 2.98 kJ

Answer 1

The correct option is A 1.49 kJ

$\eta =\frac{T_2-T_1}{T_2}=1-\frac{T_1}{T_2}=1-\frac{373}{673}=0.446\eta =\frac{△w}{q_1}or△W=\eta \times q_1=0.446\times 3.347=1.49kJ$