A certain far sighted person cannot closer to have the eye that 100cm. The power of the lens which will enable him to read at a distance of 25cm will be
A
3D
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B
1D
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C
4D
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D
2D
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Solution
The correct option is B3D v=−100cmu=−25cm1f=1v−1u1f=1(−100)−1(−25)⇒1f=3100cm−1p=1f=3100D=3100×100D=3D