A certain force acting on a body of mass 2kg increase its velocity from 6m/s to 15 m/s in 2s. The work done by the force during this interval is ?

27J

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94.5J

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189J

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Solution

The correct option is C 189J
we know that
v=u+at
15=6+a(2)
$a = 4.5 m / s^{2}$
$s = u t + 0.5 a t^{2} = 6 (2) + 0.5 (4.5) (4) = 21 m$
$W = m a s = 2 (4.5) (21) = 189 J$

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A certain force acting on a body of mass 2kg increase its velocity from 6m/s to 15 m/s in 2s. The work done by the force during this interval is ?

The correct option is C 189Jwe know that v=u+at15=6+a(2)a=4.5m/s2s=ut+0.5at2=6(2)+0.5(4.5)(4)=21mW=mas=2(4.5)(21)=189J

The correct option is C 189J
we know that
v=u+at
15=6+a(2)
$a = 4.5 m / s^{2}$
$s = u t + 0.5 a t^{2} = 6 (2) + 0.5 (4.5) (4) = 21 m$
$W = m a s = 2 (4.5) (21) = 189 J$