A certain game was played by 18 players as a team, in which only ${\frac{2}{3}}^{r d}$ of the team actually played the game. The rest were reserve players , ready to replace the main members if they get injured. How many reserve players did this team have?

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Solution

The correct options are
B
6

D

The team had $18 \times \frac{2}{3}$ = 12 main players. So, (18 - 12) = 6 players were reserve players.

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Similar questions

A certain game was played by 18 players as a team, in which only ${\frac{2}{3}}^{r d}$ of the team actually played the game. The rest were reserve players , ready to replace the main members if they get injured. How many reserve players did this team have?

A certain game was played by 18 players as a team, in which ${\frac{2}{3}}^{r d}$ of the team actually played the game, while the rest were reserve players – ready to replace the main members who got injured. How many reserve players did this team have?

A certain game was played by 18 players as a team in which ${\frac{2}{3}}^{r d}$ of the team actually played the game, while the rest were reserve players who replace the injured main members. How many reserve players did this team have?

A certain game was played by 18 players as a team, in which ${\frac{2}{3}}^{r d}$ of the team actually played the game, while the rest were reserved players - ready to replace the main members who got injured. How many reserved players did this team have?

Q. A game was played by a team of 12 players, in which only

{\frac{2}{3}}^{r d}

of the team actually played the game. The rest were reserve players. How many reserve players did this team have?

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A certain game was played by 18 players as a team, in which only 23rd of the team actually played the game. The rest were reserve players , ready to replace the main members if they get injured. How many reserve players did this team have?

The correct options are B 6 D The team had 18×23 = 12 main players. So, (18 - 12) = 6 players were reserve players.

A certain game was played by 18 players as a team, in which only ${\frac{2}{3}}^{r d}$ of the team actually played the game. The rest were reserve players , ready to replace the main members if they get injured. How many reserve players did this team have?

The correct options are
B
6

D

The team had $18 \times \frac{2}{3}$ = 12 main players. So, (18 - 12) = 6 players were reserve players.