A certain gas occupies 0-418 litre at 27 - Cl and 740 mm Hg- What is the Volume at S-T-P-A- 0-46 litreB- 0-37 litreC- 0-80 litreD- 0-50 litre

The correct option is B 0.37 litreWe Know ,P_1V_1/T_1=P_2V_2/T_2 [ By combined Gas equation] 740× 0.418/300=760× V_2/273 V_2=740× 273× 0.418/760× 3000.37 litre ...

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Standard XII

Chemistry

Percentage Composition

A certain gas...

Question

A certain gas occupies 0.418 litre at $27^{\circ}C$ and 740mm Hg. What is the Volume at S.T.P.?

0.46 litre

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0.37 litre

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0.80 litre

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0.50 litre

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Solution

The correct option is B 0.37 litre
We Know , $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ [ By combined Gas equation]
$\frac{740 \times 0.418}{300} = \frac{760 \times V_{2}}{273}$
$V_{2} = \frac{740 \times 273 \times 0.418}{760 \times 300} 0.37 l i t r e$

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A certain gas occupies 0.418 litre at \(27^{\circ}C\) and 740mm Hg. What is the Volume at S.T.P.?

The correct option is B 0.37 litreWe Know ,P1V1T1=P2V2T2 [ By combined Gas equation] 740×0.418300=760×V2273 V2=740×273×0.418760×3000.37litre

The correct option is B 0.37 litre
We Know , $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$ [ By combined Gas equation]
$\frac{740 \times 0.418}{300} = \frac{760 \times V_{2}}{273}$
$V_{2} = \frac{740 \times 273 \times 0.418}{760 \times 300} 0.37 l i t r e$