A certain gas takes three times as long to effuse out as helium. It's molecular mass will be

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Q. A certain gas takes three times as long to effuse out as helium. Its molecular mass will be :

It takes 26 s for 10 mL of $H_{2}$ to effuse through a porous membrane. It takes 130 s for 10 mL of an unknown gas to effuse. Hence, molecular weight of the unknown gas is (in $g m o l^{- 1}$ )

50 m L

of each gas

A

and of gas

B

takes

150 s

and

200 s

respectively for effusing through a pin hole under the similar conditions. If molecular mass of gas

B

36

, the molecular mass of gas

A

will be:

Q. Pure

O_{2}

diffuses through an aperture in 224 sec, whereas mixture of

O_{2}

and another gas containing
80 %

O_{2}

takes 234 sec to effuse out same volume. What is molecular weight of the gas ?

(Answer should be the closest integer to the molecular weight).

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