A certain gas ‘X’ occupies a volume of 100 ccs at S.T.P. and weighs 0.5 g. Find its relative molecular mass.

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Solution

Gas X occupies volume at S.T.P. = 100 cc
Gas X has mass = 0.5 g
100 cc of a gas X weighs = 0.5 g
22400 cc of a gas X weighs = $\frac{0.5}{100} \times 22400 = 112 g$

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A certain gas ‘X’ occupies a volume of 100 ccs at S.T.P. and weighs 0.5 g. Find its relative molecular mass.

Gas X occupies volume at S.T.P. = 100 cc Gas X has mass = 0.5 g 100 cc of a gas X weighs = 0.5 g22400 cc of a gas X weighs = 0.5100×22400=112g

Gas X occupies volume at S.T.P. = 100 cc
Gas X has mass = 0.5 g
100 cc of a gas X weighs = 0.5 g
22400 cc of a gas X weighs = $\frac{0.5}{100} \times 22400 = 112 g$