A certain gas ‘X’ occupies a volume of 100 $c m^{3}$ at STP and weighs 0.5 g.

Find its relative molecular mass.

111 g

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113 g

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112 g

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121 g

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Solution

The correct option is C
112 g

100 $c m^{3}$ of a gas will weigh 0.5 g

1 $c m^{3}$ of the gas will weigh $\frac{0.5}{100}$ gm.

$∴$ 22400 $c m^{3}$ of the gas will weigh = $\frac{0.5}{100} \times 22400 \Rightarrow 112 g .$

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A certain gas ‘X’ occupies a volume of 100 cm3 at STP and weighs 0.5 g. Find its relative molecular mass.

The correct option is C 112 g 100 cm3 of a gas will weigh 0.5 g 1 cm3​ of the gas will weigh 0.5100 gm​. ∴ 22400 cm3​​ of the gas will weigh = 0.5100×22400⇒112 g.

A certain gas ‘X’ occupies a volume of 100 $c m^{3}$ at STP and weighs 0.5 g.

Find its relative molecular mass.

The correct option is C
112 g

100 $c m^{3}$ of a gas will weigh 0.5 g

1 $c m^{3}$ of the gas will weigh $\frac{0.5}{100}$ gm.

$∴$ 22400 $c m^{3}$ of the gas will weigh = $\frac{0.5}{100} \times 22400 \Rightarrow 112 g .$