Question

A certain hotel requires $105kg$ of wheat for a week. How many $kg$ of wheat will it require for $58$ days?

• A. $406$
• B. $870$
• C. $708$
• D. $536$

Answer 1

Answer: (B)

$870$

(b) In $7$ days, amount of wheat required $=105kg$
$\therefore$ In $1$ day, the amount of wheat required $=\frac{105}{7}kg$
$\therefore$ In $58$ days, the amount of wheat required $=\frac{105}{7}\times 58kg=870kg$.