A certain job was assigned to a group of men to do in 20 days. But 12 men did not turn up for the job and the remaining men did the job in 32 days. The original number of men in the group was:
A
31
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B
30
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C
32
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D
35
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Solution
The correct option is D32
Let the original no. of men in the group be x
According to the question-
x men completes the job in 20 days.
(x−12) men completes the job in 32 days.
∴ work done by x men in 20 days = work done by (x−12) men in 32 days
⇒x×20=(x−12)×32
⇒20x=32x−384
⇒12x=384
⇒x=32
Hence, the original number of men in the group was 32.