Question

A certain mass of a gas occupies a volume of 180 $cc$ at a temperature of ${47}^{0}C$ and 2 $atm$ pressure. At what temperature the volume of the same mass of the gas becomes equal to 1000 $cc$ when pressure is changed to 5 $atm$.

• A. $7111K$
• B. ${1104}^{0}C$
• C. $4444K$
• D. ${652}^{0}C$

Answer 1

The correct option is C $4444K$

Applying the ideal gas equation; $\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$
Therefore $T_2$ = $\frac{5\times 1000\times 320}{180\times 2}$ = 4444 $K$