A certain mass of carbon required $16 g r a m s$ of oxygen to be converted into carbon monoxide. To convert $C O$ into carbon dioxide $({C O}_{2})$ , the mass of oxygen required would be:

4.0 g r a m s

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8.0 g r a m s

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12 g r a m s

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16 g r a m s

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Solution

The correct option is C $16 g r a m s$
16 gram of oxygen reputred to certain masss
$2 C + O_{2} \to 2 C O$
1mol 0.5 mol 1 mol
then all $C O$ is converted into $C O_{2}$ then
$\frac{1}{2}$ mole of $O_{2}$ is $16$ gram

answer is D

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