Question

A certain mass of Hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is 0.02866 u. The energy liberated per u is - (Given 1 u = 931 MeV)

• A. 2.67 MeV
• B. 26.7 MeV
• C. 6.675 MeV
• D. 13.35 MeV

Answer 1

The correct option is C 6.675 MeV

${}_1{H}^2{+}_1{H}^2{\to }_{2}H{e}^4$
Mass defect $=\Delta m=0.02866u$
Total energy $=E=\Delta m{c}^2=0.02866\times 931MeV$
$=26.68MeV$
Energy liberated per u $=\frac{E}{A}=\frac{26.68}{4}=6.678MeV$