Question

A certain mass of hydrogen is changed to Helium by the process of fusion. The mass defect in fusion reaction is $0.02866u$. The energy liberated per $u$ is: (given $1u=931\text{MeV}$)

• A. $13.35\text{MeV}$
• B. $2.67\text{MeV}$
• C. $26.7\text{MeV}$
• D. $6.670\text{MeV}$

Answer 1

The correct option is D $6.670\text{MeV}$

${}_1^1\text{H}{+}_1^1\text{H}\to {}_2^4\text{He}$

$\text{Energy released per}u=\frac{\text{Energy released}}{A}$

$=\frac{\Delta m}{4}\times 931\left(\text{in MeV}\right)$

$=\left(\frac{0.02866}{4}\right)\times \left(931\right)=6.670\text{MeV}$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(D\right)$ is the correct answer.