Question

A certain mass of the gas occupies a volume of 600 $ml$ at a certain temperature and pressure. If the temperature is increased by 80% what will be the volume occupied by the same mass of gas at the same pressure?

• A. 1080 $ml$
• B. 108 $ml$
• C. 120 $ml$
• D. 102 $ml$

Answer 1

The correct option is A 1080 $ml$

At constant temperature and pressure,

Applying the Charle's law equation; $\frac{V_1}{T_1}=\frac{V_2}{T_2}$,

$V_1=600$ $ml$, $V_2$ = ?

Now initial temperature ($T_1$) is increased by $80\%$,

$\therefore$If $T_1=T$, then $T_2=T+\frac{80}{100}\times T=T+\frac{4T}{5}=\frac{9T}{5}$

$\therefore$$V_2=\frac{600\times 9T}{5\times T}=1080$ $ml$

Hence, the correct answer is option $\text{A}$.