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Question

A certain metal (A) is boiled in dilute nitric acid to give a salt (B) and an oxide of nitrogen (C). An aqueous solution of (B) with brine gives a precipitate (D) which is soluble in ammonium hydroxide. On adding aqueous solution of (B) to hypo solution, a white precipitate (E) is obtained. (E) on standing turns to a black compound.Compound (A) to (F) are identified as:
(A) : Ag; (B) : AgNO3, (C) : NO2 , (D) : AgCl, (E) : Ag2S2O3 and (F) : Ag2S
If true enter 1, else enter 0.

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Solution

When silver metal (compound A) is boiled in dilute nitric acid, it forms silver nitrate (compound B) and nitrogen dioxide gas (compound C).
Ag+2HNO3boilAgNO3+NO2+H2O
Silver nitrate reacts with NaCl to form white precipitate of silver chloride (compound D) which dissolves in ammonium hydroxide.
AgNO3+NaClNaNO3AgClwhite
Silver nitrate reacts with hypo solution to form a white precipitate of Ag2S2O3 which is compound .
2AgNO3+Na2S2O3Ag2S2O3white+2naNO3
On standing Ag2S2O3 turns to black Ag2S which is compound F.
Ag2S2O3+H2OAg2Sblack+H2SO4

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