A certain non volatile non electrolyte solute contains 69.4% carbon, 11.55% nitrogen and 5.8% hydrogen (all percentage are by mass). A solution containing 40% by weight of this substance boils at 100.11degree celcius. The Kb=0.04K kg/mol and the boiling point of pure solvent is 373K. What is the formula of the compound?

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Q. A certain non-volatile electrolyte contains 40% carbon , 6.7% hydrogen and 53.3% oxygen . An aqueous solution containing 5% by mass of the solute boils at 100.

15^{\circ} C .

Determine the molecular formula of the compound

(K_{b} = {0.5}^{\circ} C / m) :

Q. A solution containing

12.5 g

of non-electrolyte substance in

185 g

of water shows boiling point elevation of

0.80 K

. Calculate the molar mass of the substance. (

K_{b} = 0.52 K

k g

{m o l}^{- 1}

)

Q. Why does a solution containing non - volatile solute have higher boiling point than the pure solvent ? Why is elevation of boiling point a colligative property?

Fill in the blank.
Boiling point of solution containing a non volatile solute is always ---- the boiling point of pure solvent in which solution is prepared.

For a dilute solution containing 2.5 g of a non-volatile non-electrolyte solute in 100 g of water, the elevation in boiling point at 1 atm pressure is $2^{\circ} C$ . Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is (take $K_{b}$ =0.76K kg $m o l^{- 1}$ ).

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