Question

A certain nucleus $\mathrm{\chi }$ has a mass number $14$ and atomic number $6$. The nucleus $\mathrm{\chi }$ changes to ${}_{7}Y^{14}$after the loss of a particles. What is the name of particles emitted and represent this changes in the form of an equation.

Answer 1

1. Mass number of nucleus $\mathrm{\chi }$ is $14$ and atomic number is $6$.
2. The nucleus $\mathrm{\chi }$ changes to nucleus ${}_{7}Y^{14}$.
3. So mass number of nucleus $\mathrm{Y}$ is also $14$ and atomic number of nucleus $\mathrm{y}$ is $7$.
4. Now mass number of nucleus $\mathrm{\chi }$ and $\mathrm{Y}$ are same but atomic number of $\mathrm{Y}$ increase by one unit.
5. We known that if the nucleus emits $\mathrm{\beta }$-particles, its mass number remains same but atomic number increases by one unit.
6. Hence, the name of the particles is emitted in this process is $\mathrm{\beta }$- particles .
7. This change is represented in the form of an equation is given below

${}_6\mathrm{\chi }^{14}\to {}_7\mathrm{Y}^{14}+{}_{-1}{}^{°}\mathrm{\beta }+\mathrm{energy}.$