A certain nucleus $X$ has a mass number 14 and atomic number 6. The nucleus $X$ changes to $_{7}^{14} Y$ after the loss of a particle. Represent this change in the form of an equation.

Open in App

Solution

Here, only atomic number is changing from $6$ to $7$ , therefore the nucleus is undergoing a beta decay. Its equation is given as:

$_{6}^{14} X \to_{7}^{14} Y +_{- 1}^{0} e$

Suggest Corrections

Similar questions

Q. A certain nucleus

X

has a mass number 14 and atomic number 6. The nucleus

X

changes to

_{7}^{14} Y

after the loss of a particle. Name the particle emitted.

Q. A certain nucleus X has a mass number 14 and atomic number 6. The nucleus X changes to Y14 after the loss of a particle.
(a) Name the particle emitted.
(b) Represent this change in the form of an equation.
(c) A radioactive substance is oxidized. What change would you expect to take place in the nature of its radioactivity? Give a reason for your answer.
[5 MARKS]

Q. A certain nucleus A (mass number 238 and atomic number 92) is radioactive and becomes a nucleus (mass number 234 and atomic number 90) by the loss of a particle. State the change in the form of a reaction.

Q. A nucleus X has a mass number 12 and atomic number 6. Calculate the number of neutrons and protons, when the nucleus X loses :
(a) One proton
(b) One neutron.
Write the changes in symbolic form.
[4 MARKS]

Consider a radioactive element with the nucleus 'X' having the atomic number A and the mass number Z. It emits an α particle. The change thus happens from the parent nucleus X to the daughter nucleus Y can be expressed as:

$_{Z}^{A} X Parent nucleus \to_{Z - 4}^{A - 2} Y Daughter nucleus +_{2}^{4} H e (α - particle)$

Join BYJU'S Learning Program

A certain nucleus X has a mass number 14 and atomic number 6. The nucleus X changes to 147Y after the loss of a particle. Represent this change in the form of an equation.

Here, only atomic number is changing from 6 to 7, therefore the nucleus is undergoing a beta decay. Its equation is given as: 146X → 147Y+ 0−1e

A certain nucleus $X$ has a mass number 14 and atomic number 6. The nucleus $X$ changes to $_{7}^{14} Y$ after the loss of a particle. Represent this change in the form of an equation.

Here, only atomic number is changing from $6$ to $7$ , therefore the nucleus is undergoing a beta decay. Its equation is given as:

$_{6}^{14} X \to_{7}^{14} Y +_{- 1}^{0} e$