Question

A certain number of camels and an equal number of men are going somewhere. Half of the owners are on their camel's back, while the remaining ones are walking along leading their camels. If the number of legs walking on the ground is $70$, how many camels are there?

Answer 1

$Lettherebexnumberofcamels=numberofmen,Menoncamels=menonfoot=\frac{x}{2},Numberoflegsonground=4\times x\left(camels\right)+2\times \frac{x}{2}\left(men\right)=70⟹5x=70,x=14$