A certain number of identical condensers are first connected in series and then in parallel. If the equivalent capacities in the two cases are found to be in the ratio 1: 9, what is the number of condensers?

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Solution

The correct option is B 3
$\frac{C_{s} e r i e s}{C_{p} a r a l l e l} = \frac{(\frac{C}{n})}{n c} = \frac{1}{n^{2}}$
$\frac{1}{9} = \frac{1}{n^{2}}$
$n = 3$

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A certain number of identical condensers are first connected in series and then in parallel. If the equivalent capacities in the two cases are found to be in the ratio 1: 9, what is the number of condensers?

The correct option is B 3CseriesCparallel=(Cn)nc=1n2 19=1n2 n=3

The correct option is B 3
$\frac{C_{s} e r i e s}{C_{p} a r a l l e l} = \frac{(\frac{C}{n})}{n c} = \frac{1}{n^{2}}$
$\frac{1}{9} = \frac{1}{n^{2}}$
$n = 3$