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Question

A certain of gas is expanded from (1L,10atm) to (4L,5atm) against a constant external pressure of 1atm. If the initial temperature of a gas is 300K, and the heat capacity of the process is 50J/degree celsius. The change during the reaction is: (1L atm= 100J)

A
ΔH=15KJ
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B
ΔH=15.7KJ
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C
ΔH=14.4KJ
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D
ΔH=14.7KJ
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Solution

The correct option is A ΔH=15.7KJ
For the state 1
PV=nRT
1×10=n(0.0821)(300)
n=0.4

For the state 2
PV=nRT
4×5=0.4×(0.0821)(T2)
T2=600 K

ΔU=q+W
=50(ΔT)+(Pex)(ΔV)
=50(600300)(1)(41) (In L-atm)
=15000300 (In joule)
=14700 J
ΔH=ΔU+Δ(PV)

=14700+(5×410×1)×100 (1 L-atm = 100J)
=15700 J
=15.7 kJ or

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