A certain particle carries $2.5 \times 10^{- 16} C$ of static electric charge. Calculate the number of electrons present in it.

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Solution

One electron has charge $1.602 \times 10^{- 19} C$ .

The number of electrons present in the charged particle is $\frac{2.5 \times 10^{- 16}}{1.602 \times 10^{- 19}} = 1.56 \times 10^{3}$ .

thus, the number of electrons present in the charged particle is $= 1.56 \times 10^{3}$ .

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A certain particle carries 2.5×10−16C of static electric charge. Calculate the number of electrons present in it.

One electron has charge 1.602×10−19C.The number of electrons present in the charged particle is 2.5×10−161.602×10−19=1.56×103.thus, the number of electrons present in the charged particle is =1.56×103.

A certain particle carries $2.5 \times 10^{- 16} C$ of static electric charge. Calculate the number of electrons present in it.

One electron has charge $1.602 \times 10^{- 19} C$ .

The number of electrons present in the charged particle is $\frac{2.5 \times 10^{- 16}}{1.602 \times 10^{- 19}} = 1.56 \times 10^{3}$ .

thus, the number of electrons present in the charged particle is $= 1.56 \times 10^{3}$ .