CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A certain quantity of electricity is passed through aqueous $$Al_2(SO_4)_3$$ and $$CuSO_4$$ solutions connected in series $$0.09$$ g of Al is deposited on cathode during electrolysis. The amount of copper deposited on cathode in grams is:
(At. wt of Al$$=27;$$ Cu$$=63.6$$)


A
31.8
loader
B
0.636
loader
C
3.18
loader
D
0.318
loader

Solution

The correct option is D $$0.318$$
Let $$W$$ g of $$Cu$$ is deposited at the cathode.

Using the second law of electrolysis:

$$\dfrac{W_1}{E_1}=\dfrac{W_2}{E_2}$$

$$\displaystyle  \dfrac {W_1\times 2}{63.6} =  \dfrac {0.09\times 3}{27} $$

$$\displaystyle W_1 = 0.318\ g$$

Chemistry

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image