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Standard XII

Chemistry

Faraday's Second Law

A certain qua...

Question

A certain quantity of electricity is passed through aqueous $A l_{2} (S O_{4})_{3}$ and $C u S O_{4}$ solutions connected in series $0.09$ g of Al is deposited on cathode during electrolysis. The amount of copper deposited on cathode in grams is:
(At. wt of Al $= 27;$ Cu $= 63.6$ )

31.8

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0.636

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3.18

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0.318

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Solution

The correct option is D $0.318$
Let $W$ g of $C u$ is deposited at the cathode.

Using the second law of electrolysis:

$\frac{W_{1}}{E_{1}} = \frac{W_{2}}{E_{2}}$

$\frac{W_{1} \times 2}{63.6} = \frac{0.09 \times 3}{27}$

$W_{1} = 0.318 g$

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A certain quantity of electricity is passed through aqueous Al2(SO4)3 and CuSO4 solutions connected in series 0.09 g of Al is deposited on cathode during electrolysis. The amount of copper deposited on cathode in grams is:(At. wt of Al=27; Cu=63.6)

The correct option is D 0.318Let W g of Cu is deposited at the cathode.Using the second law of electrolysis:W1E1=W2E2W1×263.6=0.09×327W1=0.318 g

A certain quantity of electricity is passed through aqueous $A l_{2} (S O_{4})_{3}$ and $C u S O_{4}$ solutions connected in series $0.09$ g of Al is deposited on cathode during electrolysis. The amount of copper deposited on cathode in grams is:
(At. wt of Al $= 27;$ Cu $= 63.6$ )

The correct option is D $0.318$
Let $W$ g of $C u$ is deposited at the cathode.

Using the second law of electrolysis:

$\frac{W_{1}}{E_{1}} = \frac{W_{2}}{E_{2}}$

$\frac{W_{1} \times 2}{63.6} = \frac{0.09 \times 3}{27}$

$W_{1} = 0.318 g$