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Question

A certain radioactive sample is obtained by mixing equal number of nuclides of species A and species B. Half life of species A is T and that of B is 2T. After certain time, it is found that the remaining radioactive nuclei of A and B combined together are 532 of the total number of nuclei. The number of half-lives of A that elapsed is

A
4
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B
3
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C
2
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D
1
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Solution

The correct option is A 4
As, N=(N22n+N22n/2)
Where n is number of half lives elapsed for species A.
Now NN=532=[12n+1+12n2+1]
On solving, we get, n = 4

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