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Question

A certain reaction is non-spontaneous at 300 K. The entropy change during the reaction is 120JK1. Then the minimum value of ΔH for the reaction and the nature of the reaction will be:

A
36.0 kJ; endothermic
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B
36.0 kJ; exothermic
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C
2.8 kJ; endothermic
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D
2.8 kJ; exothermic
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Solution

The correct option is A 36.0 kJ; endothermic
For non-spontaneous reactions, ΔG is +ve.
ΔG=ΔHTΔS; ΔS is +120JK1
To make ΔG as +ve,ΔH should be +ve, i.e., endothermic
For minimum value of entropy,
ΔH=TΔS
=300×120=36000J
=36.0kJ

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