wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A certain region of a soap bubble reflects red light of vacuum wavelength λ=650nm. What is the minimum thickness that this region of the soap bubble could have? Take the index of reflection of the soap film to be 1.41

A
1.2×107m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
650×109m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
120×107m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
650×105m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 1.2×107m
By equation of destructive interference,
thickness, t=12(m+0.5)λ1.41
where m is any non-negative integer,
λ=650109.
For minimum thickness, take m=0
So, t=1.1521071.2107

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Optical Path
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon