A certain region of a soap bubble reflects red light of vacuum wavelength λ=650nm . The minimum thickness that this region of soap bubble could have is 13×10−xm. Find x.
( The index of refraction of the soap film is 1.25)
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Solution
If t be the thickness of the bubble, then 4μt=λ Substituting the values, t=6×10−94×1.25 This gives, t=13×10−8 Thus, x=8