A certain sound has a frequency of 256 Hz and a wavelength of 1.3 m. Calculate the speed with which this sound travels. What difference would be felt by a listener between the above sound and another sound travelling at the same speed, but of wavelength 2.6 m?

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Solution

$S p e e d = w a v e l e n g t h \times f r e q u e n c y$
$= 1.3 \times 256 = 332.8 m / s$
Now,
wavelength given = 2.6 m (double of first wavelength)
Speed = 332.8 m/s (Given)
$∴ F r e q u e n c y = \frac{s p e e d}{w a v e l e n g t h}$
$= \frac{332.8}{2.6}$
$= 128 h e r t z$
The difference between the sounds would be that the sound with the greater wavelength (2.6 m) will have a higher pitch than the sound with the less frequency.

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