A certain string (fixed at one end and free at the other end) can vibrate at several frequencies, the lowest of which is 200Hz. What are next two higher frequencies to which it vibrates?
A
600Hz,1000Hz
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B
300Hz,400Hz
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C
200Hz,250Hz
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D
100Hz,150Hz
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Solution
The correct option is A600Hz,1000Hz Frequency of vibration will be given by, f=(n+12)V2L The lowest frequency is the fundamental frequency of vibration i.e for n=0 ⇒fmin=V4L=f0 Given: f0=200Hz for next higher frequencies (n=1,n=2) ⇒f1=3V4L=3f0=600Hz f2=5V4L=5f0=1000Hz