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Question

A certain string (fixed at one end and free at the other end) can vibrate at several frequencies, the lowest of which is 200 Hz. What are next two higher frequencies to which it vibrates?

A
600 Hz, 1000 Hz
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B
300 Hz,400 Hz
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C
200 Hz,250 Hz
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D
100 Hz,150 Hz
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Solution

The correct option is A 600 Hz, 1000 Hz
Frequency of vibration will be given by,
f=(n+12)V2L
The lowest frequency is the fundamental frequency of vibration i.e for n=0
fmin=V4L=f0
Given: f0=200 Hz
for next higher frequencies (n=1, n=2)
f1=3V4L=3f0=600 Hz
f2=5V4L=5f0=1000 Hz

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