A certain sum of money becomes three times of itself in $20$ years at simple interest. In how many years does it become double of itself at the same rate?

8

years

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10

years

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12

years

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14

years

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Solution

The correct option is A $10$ years
(b) Let the principal $= R s . x$ . Amount $= R s . 3 x$ , Time $= 20$ years
$∴ S . I . = R s . 3 x - R s . x = R s . 2 x$
Rate $= (\begin{matrix} \frac{2 x \times 100}{x \times 20} \end{matrix}) % p . a . = 10 % p . a .$
Now, Principal $= R s . x$ , Amount $= R s . 2 x$ , Rate $= 10 % p . a .$
$S . I . = R s . 2 x - R s . x = R s . x$
$∴$ Time $= \frac{x \times 100}{x \times 10} = 10$ years.

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A certain sum of money becomes three times of itself in 20 years at simple interest. In how many years does it become double of itself at the same rate?

The correct option is A 10 years(b) Let the principal =Rs.x. Amount =Rs.3x, Time =20 years∴S.I.=Rs.3x−Rs.x=Rs.2x Rate =(2x×100x×20)%p.a.=10%p.a. Now, Principal =Rs.x, Amount =Rs.2x, Rate =10%p.a.S.I.=Rs.2x−Rs.x=Rs.x∴ Time =x×100x×10=10 years.

A certain sum of money becomes three times of itself in $20$ years at simple interest. In how many years does it become double of itself at the same rate?