A certain sum of money lent out at a certain rate of interest per annum, doubles itself in 10 years. In how many years will it treble itself?

20 years

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16 years

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12 years

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10 years

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Solution

The correct option is A 20 years
$R_{1} = R_{2}; T_{1} = 10 y e a r s; N_{1} = 2;$

$N_{2} = 3; T_{2} = ?$

We have
$\frac{R_{1} \times T_{1}}{R_{2} \times T_{2}} = \frac{N_{1} - 1}{N_{2} - 1}$

$\frac{R_{1} \times 10}{R_{1} \times T_{2}} = \frac{2 - 1}{3 - 1}$

$T_{2} = 20$ years.

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A certain sum of money lent out at a certain rate of interest per annum, doubles itself in 10 years. In how many years will it treble itself?

The correct option is A 20 yearsR1=R2;T1=10years;N1=2;N2=3;T2=?We haveR1×T1R2×T2=N1−1N2−1R1×10R1×T2=2−13−1T2=20 years.

The correct option is A 20 years
$R_{1} = R_{2}; T_{1} = 10 y e a r s; N_{1} = 2;$

$N_{2} = 3; T_{2} = ?$

We have
$\frac{R_{1} \times T_{1}}{R_{2} \times T_{2}} = \frac{N_{1} - 1}{N_{2} - 1}$

$\frac{R_{1} \times 10}{R_{1} \times T_{2}} = \frac{2 - 1}{3 - 1}$

$T_{2} = 20$ years.