Let principal be P and rate of interest be R.
So in 3 years , Interest I=P×R×T100=3PR100
Amount(A)=P+I⇒1550=P+3PR100⇒P(1+3R100)=1550...(1)
And in 5 years , Interest I=P×R×T100=5PR100
Amount(A)=P+I⇒1750=P+5PR100⇒P(1+5R100)=1750...(2)
Dividing equation 1 and 2 we have,
P(1+3R100)P(1+5R100)=15501750
⇒(100+3R)(100+5R)=3135
⇒35(100+3R)=31(100+5R)
⇒155R−105R=3500−3100
⇒50R=400
⇒R=8
Putting the value of R in equation 1,
P(1+3×8100)=1550
P=1550×100124=1250