Question

A certain transverse wave is described by
$y(x,t)=\left(6.50mm\right)cos2\pi (\frac{x}{28.0cm}-\frac{t}{0.0360s})$
The wave's amplitude is $6.50\times {10}^{-x}m.$ Find the value of x.

Answer 1

A right travelling transverse wave has form $y=Acos(kx-\omega t)$

where $A$ is the wavelength of the wave,

$k=\frac{2\pi }{\lambda }$, $\lambda$ is the wavelength

$\omega =2\pi \nu$, $\nu$ is the frequency of the wave

Thus Amplitude of wave $\left(6.50mm\right)cos2\pi (\frac{x}{28.0cm}-\frac{t}{0.0360s})$

is $A=6.50mm$