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Question

A certain volume of H2 effuses from an apparatus in one minute. The same volume of ozonized oxygen (O3+O2 mix) took 246 s to effuse from the apparatus under identical conditions. Find the % of oxygen in the ozonized oxygen.

A
89.87
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B
99.87
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C
79.87
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D
69.87
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Solution

The correct option is A 89.87
Let the molecular weight of the mixture (O3+O2) be M2.

From
rH2rg=M2M1
V/t1V/t2=M2M1
t2t1=M2M1
24660=M22M2=33.62 (average mol. wt. of O3+O2)
Let the mol % of O3 be a and the mol % of O2=100a
The average molecular weight =a×48+(100a)32100
33.62=a×48+(100a)32100
a=10.125
O3=10.125 O2=89.875

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