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Hardness of Water and Treatment

A certain wat...

Question

A certain water needs alum treatment to the extent of 10 p.p.m. How much alum, in quintals per day, would be needed to treat 10 MLD of water?

A

10

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B

100

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C

1.0

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D

1000

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Solution

The correct option is C 1.0
(b) Alum needed

$= 10 M L D \times 10 p p m$

$= 10 \times 10^{6} L / d a y \times 10 m g / L$

$= 100 \times 10^{6} m g / d a y = 100 k g / d a y$

$= 1 q u i n t a l / d a y$

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