A certain weak acid has a dissociation constant of 1- 10 -4-The equilibrium for its reaction with a strong base is-

The correct option is C 1× 10 ^ 10 ...

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A certain wea...

Question

A certain weak acid has a dissociation constant of $1 \times 10^{- 4}$ .The equilibrium for its reaction with a strong base is:

1 \times 10^{- 4}

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1 \times 10^{- 10}

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1 \times 10^{10}

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1 \times 10^{14}

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Solution

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1.0 \times 10^{- 4}

1.0 \times 10^{- 4}

K_{a} = 1.0 \times 10^{- 4}

K_{a} = 1 \times 10^{- 4} . K_{e q}

K_{a} = 10^{- 5}

y \times 10^{10}

y

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