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A certain x-r...

Question

A certain x-ray tube operates at a current of $7.00$ mA and a
potential difference of $80.0$ kV. What is its power in watts?

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Solution

The power dissipated is given by the product of the current and the potential
difference: $P = i V = (70 \times 10^{- 3} A) (80 \times 10^{3} V) = 560 W$ .

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