$a^{\frac{4}{3}} \div a^{- \frac{2}{3}} =$

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Solution

Given
$a^{\frac{4}{3}} \div a^{- \frac{2}{3}} = \frac{a^{\frac{4}{3}}}{a^{- \frac{2}{3}}}$
$= a^{\frac{4}{3} - ⎛ ⎝ - \frac{2}{3} ⎞ ⎠}$
$= a^{\frac{4}{3} + \frac{2}{3}}$
$= a^{\frac{4 + 2}{3}}$
$= a^{\frac{6}{3}}$
$= a^{2}$

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Similar questions

a^{\frac{4}{3}} \div a^{- \frac{2}{3}}

a^{\frac{4}{3}} \div a^{- \frac{2}{3}}

a^{2}

e^{2} - 1 = \frac{1 + \frac{a^{2}}{2!} + \frac{a^{4}}{3!} + \frac{a^{6}}{4!} + . . .}{1 + \frac{1}{2!} + \frac{2}{3!} + \frac{2^{2}}{4!} + . . .}

a

a_{4}

a_{1} = 2, r = - 3

A = [\begin{matrix} - 3 & 0 \\ 0 & - 3 \end{matrix}]

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