Question

A chain having $125$ links is $i25$ cm long. Its mass is $2$ Kg. Its two ends are connected and the chain is rotated with a frequency $50$ revolution per second. calculate the centripetal force on each link.

Answer 1

Solution $f=50H_2$

$w=2\pi \times f=2\pi \times 50=100\pi ,rod/s$

$R=(125-2)\left(25/100\right)cm$

$R_{com}=R/2=\frac{123}{2}\times \frac{1}{4}m$

Centripetal force $=\frac{m(V_{com}{)}^2}{R_{com}}=V\frac{\left(w{R}_{com}\right)}{R_{com}}$

$f=m{w}^2{R}_{com}$

$f=2\left(100\pi {)}^2\right(\frac{123}{8})=3.03\times {10}^{6}N$