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Question

A chain in the shape of circular loop of mass m and radius R is placed on a frictionless surface. Loop is given an angular velocity of ω as shown in the figure. Tension in the chain is

A
mω2R
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B
mω2R2π
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C
mω2R2
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D
mω2Rπ
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Solution

The correct option is B mω2R2π

dm=m2πRdl=m2πR(2Rθ)
For equilibrium
2Tsinθ=2Tθ=dmω2R2Tθ/=m(2θ/)2πω2RT=mω2R2π

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